Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

If yy varies inversely with xx and y=2y = 2 when x=4x = 4, find yy when x=1x = 1. \newlineWrite and solve an inverse variation equation to find the answer.\newliney=y = _____

Full solution

Q. If yy varies inversely with xx and y=2y = 2 when x=4x = 4, find yy when x=1x = 1. \newlineWrite and solve an inverse variation equation to find the answer.\newliney=y = _____
  1. Define Inverse Variation: Inverse variation means y=kxy = \frac{k}{x}. We need to find kk using the given values y=2y = 2 and x=4x = 4.
  2. Substitute Values: Substitute y=2y = 2 and x=4x = 4 into y=kxy = \frac{k}{x} to find kk.2=k42 = \frac{k}{4}
  3. Solve for k: Multiply both sides by 44 to solve for kk.2×4=k2 \times 4 = k
  4. Final Inverse Variation Equation: k=8k = 8. Now we have the inverse variation equation y=8xy = \frac{8}{x}.
  5. Find yy for x=1x=1: Find yy when x=1x = 1 using the equation y=8xy = \frac{8}{x}.\newliney=81y = \frac{8}{1}
  6. Find yy for x=1x=1: Find yy when x=1x = 1 using the equation y=8xy = \frac{8}{x}.y=81y = \frac{8}{1}y=8y = 8. So when x=1x = 1, y=8y = 8.

More problems from Write and solve inverse variation equations