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If yy varies directly with xx and y=4y = 4 when x=2x = 2, find yy when x=1x = 1. Write and solve a direct variation equation to find the answer.\newlineyy = ____

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Q. If yy varies directly with xx and y=4y = 4 when x=2x = 2, find yy when x=1x = 1. Write and solve a direct variation equation to find the answer.\newlineyy = ____
  1. Determine Equation: Determine the equation that represents the direct variation.\newlineSince yy varies directly with xx, the relationship can be described by the equation y=kxy = kx, where kk is the constant of variation.
  2. Find Constant of Variation: Use the given values to find the constant of variation kk. We are given that y=4y = 4 when x=2x = 2. Plugging these values into the direct variation equation gives us 4=k×24 = k \times 2.
  3. Solve for k: Solve for k.\newlineDividing both sides of the equation by 22 gives us k=42k = \frac{4}{2}, which simplifies to k=2k = 2.
  4. Write Equation with kk: Write the direct variation equation using the found value of kk. Now that we know k=2k = 2, the direct variation equation is y=2xy = 2x.
  5. Find yy for x=1x = 1: Find yy when x=1x = 1 using the direct variation equation.\newlineSubstitute x=1x = 1 into the equation y=2xy = 2x to get y=2×1y = 2 \times 1, which simplifies to y=2y = 2.

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