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If yy varies directly with xx and y=20y = 20 when x=5x = 5, find yy when x=3x = 3. Write and solve a direct variation equation to find the answer.\newlineyy = ____

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Q. If yy varies directly with xx and y=20y = 20 when x=5x = 5, find yy when x=3x = 3. Write and solve a direct variation equation to find the answer.\newlineyy = ____
  1. Establish direct variation equation: Establish the direct variation equation.\newlineSince yy varies directly with xx, the equation can be written as y=kxy = kx, where kk is the constant of variation.
  2. Find constant of variation: Use the given values to find the constant of variation kk. We are given that y=20y = 20 when x=5x = 5. Substituting these values into the direct variation equation gives us 20=k×520 = k \times 5.
  3. Solve for k: Solve for k.\newlineDivide both sides of the equation by 55 to isolate kk.\newline205=(k×5)5\frac{20}{5} = \frac{(k \times 5)}{5}\newlinek=4k = 4
  4. Write equation with kk: Write the direct variation equation with the found value of kk. Now that we know k=4k = 4, the direct variation equation is y=4xy = 4x.
  5. Find yy for x=3x=3: Find yy when x=3x = 3.\newlineSubstitute x=3x = 3 into the direct variation equation y=4xy = 4x.\newliney=4×3y = 4 \times 3\newliney=12y = 12

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