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If yy varies directly with xx and y=14y = 14 when x=2x = 2, find yy when x=1x = 1. Write and solve a direct variation equation to find the answer.\newlineyy = ____

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Q. If yy varies directly with xx and y=14y = 14 when x=2x = 2, find yy when x=1x = 1. Write and solve a direct variation equation to find the answer.\newlineyy = ____
  1. Select equation for direct variation: Select the equation that represents direct variation.\newlineSince yy varies directly with xx, we can use the direct variation equation: y=kxy = kx.
  2. Substitute values into equation: We know that y=14y = 14 when x=2x = 2. Substitute the values into the direct variation equation y=kxy = kx. Plug in 22 for xx and 1414 for yy in y=kxy = kx to find the constant of proportionality kk. 14=k×214 = k \times 2
  3. Solve for constant of proportionality: Solve for the constant of proportionality kk.\newlineDivide both sides by 22 to isolate kk.\newline142=(k×2)2\frac{14}{2} = \frac{(k \times 2)}{2}\newline7=k7 = k
  4. Write direct variation equation: Write the direct variation equation using the value of kk.\newlineSince we found that k=7k = 7, the direct variation equation is y=7xy = 7x.
  5. Find yy when x=1x = 1: Use the direct variation equation to find yy when x=1x = 1. Substitute 11 for xx in the equation y=7xy = 7x. y=7×1y = 7 \times 1 y=7y = 7

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