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If x+1x=8x +\frac{1}{x} = 8, what is xx

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Q. If x+1x=8x +\frac{1}{x} = 8, what is xx
  1. Identify equation and ask: Identify the equation given and what is asked.\newlineWe are given the equation x+1x=8x + \frac{1}{x} = 8 and we need to find the value of xx.
  2. Eliminate fraction by multiplication: Multiply both sides of the equation by xx to eliminate the fraction.\newline(x)(x)+(1x)(x)=8(x)(x)(x) + \left(\frac{1}{x}\right)(x) = 8(x)\newlineThis gives us x2+1=8xx^2 + 1 = 8x.
  3. Rearrange to form quadratic equation: Rearrange the equation to form a quadratic equation.\newlineBring all terms to one side of the equation to set it equal to zero.\newlinex28x+1=0x^2 - 8x + 1 = 0
  4. Solve using quadratic formula: Solve the quadratic equation using the quadratic formula.\newlineThe quadratic formula is x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where a=1a = 1, b=8b = -8, and c=1c = 1.
  5. Calculate discriminant to determine roots: Calculate the discriminant b24acb^2 - 4ac to determine the nature of the roots.\newlineDiscriminant = (8)24(1)(1)=644=60(-8)^2 - 4(1)(1) = 64 - 4 = 60
  6. Calculate possible values using formula: Calculate the two possible values for xx using the quadratic formula.\newlinex=8±602x = \frac{8 \pm \sqrt{60}}{2}\newlinex=8±2152x = \frac{8 \pm 2\sqrt{15}}{2}\newlinex=4±15x = 4 \pm \sqrt{15}
  7. Check solutions satisfy original equation: Check both solutions to ensure they satisfy the original equation.\newlineFor x=4+15x = 4 + \sqrt{15}, check if (4+15)+1(4+15)=8(4 + \sqrt{15}) + \frac{1}{(4 + \sqrt{15})} = 8.\newlineFor x=415x = 4 - \sqrt{15}, check if (415)+1(415)=8(4 - \sqrt{15}) + \frac{1}{(4 - \sqrt{15})} = 8.

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