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If the temperature at $6$ AM was $18\degree F$ , and $6$ hours later it dropped to $18\degree$ below zero, what was the temperature’s rate of change? $\newline$ E. $4\degree$ per hour $\newline$ F. $5\degree$ per hour $\newline$ G. $6\degree$ per hour $\newline$ H. $8\degree$ per hour

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Understanding integers

Full solution

Q. If the temperature at

6

AM was

18\degree F

, and

6

hours later it dropped to

18\degree

below zero, what was the temperature’s rate of change?

\newline

E.

4\degree

per hour

\newline

F.

5\degree

per hour

\newline

G.

6\degree

per hour

\newline

H.

8\degree

per hour

Initial Temperature: At $6$ AM the temperature was $18\degree F$ . Six hours later, it dropped to $18\degree$ below zero, which is $-18\degree F$ .
Calculate Rate of Change: To find the rate of change, subtract the final temperature from the initial temperature: $-18\degree F - 18\degree F$ .
Total Change Calculation: The calculation gives us $-18\degree F - 18\degree F = -36\degree F$ . This is the total change over $6$ hours.
Calculate Rate per Hour: Now, divide the total change by the number of hours to find the rate of change per hour: $-36\degree F \div 6$ hours.
Final Rate of Change: The rate of change is $-36\,^\circ\mathrm{F} \div 6\,\text{hours} = -6\,^\circ\mathrm{F}$ per hour.

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