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If the sum of three consecutive even integers is 60 , what is the first of the three even integers? (Hint: If 
x and 
x+2 represent the first two consecutive even integers, then how would the third consecutive even integer be represented?)
The first of the three even integers is

If the sum of three consecutive even integers is 6060 , what is the first of the three even integers? (Hint: If x x and x+2 x+2 represent the first two consecutive even integers, then how would the third consecutive even integer be represented?)\newlineThe first of the three even integers is

Full solution

Q. If the sum of three consecutive even integers is 6060 , what is the first of the three even integers? (Hint: If x x and x+2 x+2 represent the first two consecutive even integers, then how would the third consecutive even integer be represented?)\newlineThe first of the three even integers is
  1. Write equation: Now, we know that the sum of these three numbers is 6060. So we write the equation: x+(x+2)+(x+4)=60x + (x + 2) + (x + 4) = 60.
  2. Subtract to isolate: Subtract 66 from both sides to isolate the 3x3x term: 3x+66=6063x + 6 - 6 = 60 - 6.
  3. Divide to solve: Now, divide both sides by 33 to solve for xx: 3x3=543\frac{3x}{3} = \frac{54}{3}.
  4. Find first integer: So, the first of the three consecutive even integers is 1818.

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