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If the sum of three consecutive even integers is 12 , what is the first of the three even integers? (Hint: If 
x and 
x+2 represent the first two consecutive even integers, then how would the third consecutive even integer be represented?)
The first of the three even integers is 
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If the sum of three consecutive even integers is 1212 , what is the first of the three even integers? (Hint: If x x and x+2 x+2 represent the first two consecutive even integers, then how would the third consecutive even integer be represented?)\newlineThe first of the three even integers is \square

Full solution

Q. If the sum of three consecutive even integers is 1212 , what is the first of the three even integers? (Hint: If x x and x+2 x+2 represent the first two consecutive even integers, then how would the third consecutive even integer be represented?)\newlineThe first of the three even integers is \square
  1. Define Even Integers: Let xx be the first even integer.\newlineThe second even integer is x+2x + 2.\newlineThe third even integer is x+4x + 4.
  2. Set Up Equation: Set up the equation: x+(x+2)+(x+4)=12x + (x + 2) + (x + 4) = 12.
  3. Combine Like Terms: Combine like terms: 3x+6=123x + 6 = 12.
  4. Subtract and Simplify: Subtract 66 from both sides: 3x=1263x = 12 - 6.
  5. Solve for x: Solve for x: 3x=63x = 6.
  6. Divide and Calculate: Divide both sides by 33: x=63x = \frac{6}{3}.
  7. Divide and Calculate: Divide both sides by 33: x=63x = \frac{6}{3}.Calculate the value of xx: x=2x = 2.

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