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If the sum of three consecutive even integers is 78 , what is the first of the three even integers? (Hint: If 
x and 
x+2 represent the first two consecutive even integers, then how would the third consecutive even integer be represented?)
ion 5
The first of the three even integers is 
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If the sum of three consecutive even integers is 7878 , what is the first of the three even integers? (Hint: If x x and x+2 x+2 represent the first two consecutive even integers, then how would the third consecutive even integer be represented?)\newlineion 55\newlineThe first of the three even integers is \square

Full solution

Q. If the sum of three consecutive even integers is 7878 , what is the first of the three even integers? (Hint: If x x and x+2 x+2 represent the first two consecutive even integers, then how would the third consecutive even integer be represented?)\newlineion 55\newlineThe first of the three even integers is \square
  1. Define Even Integers: Let xx be the first even integer, then the second and third even integers are x+2x+2 and x+4x+4 respectively
  2. Calculate Sum: The sum of these three consecutive even integers is x+(x+2)+(x+4)x + (x + 2) + (x + 4)
  3. Set Up Equation: We know the sum is 7878, so we set up the equation: x+(x+2)+(x+4)=78x + (x + 2) + (x + 4) = 78
  4. Combine Like Terms: Combine like terms: 3x+6=783x + 6 = 78
  5. Subtract 66: Subtract 66 from both sides: 3x=7863x = 78 - 6
  6. Simplify Equation: Simplify the right side: 3x=723x = 72
  7. Divide by 33: Divide both sides by 33 to solve for xx: x=723x = \frac{72}{3}
  8. Calculate x: Calculate the value of x: x=24x = 24
  9. Find First Integer: The first even integer is 2424, so the answer is 2424

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