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If the sum of the measures of the interior angles of a polygon is 1980^(@), how many sides does the polygon have?

If the sum of the measures of the interior angles of a polygon is 1980∘1980^\circ, how many sides does the polygon have?

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Full solution

Q. If the sum of the measures of the interior angles of a polygon is 1980∘1980^\circ, how many sides does the polygon have?
  1. Calculate sum of angles: Calculate the sum of the interior angles using the formula (n−2)×180(n-2) \times 180, where nn is the number of sides.(n−2)×180=1980(n-2) \times 180 = 1980
  2. Solve for n: Solve for n.\newlinen−2=1980180n - 2 = \frac{1980}{180}\newlinen−2=11n - 2 = 11\newlinen=13n = 13

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