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If the probability that the Islanders will beat the Rangers in a game is 
18%, what is the probability that the Islanders will win exactly one out of six games in a series against the Rangers? Round your answer to the nearest thousandth.
Answer:

If the probability that the Islanders will beat the Rangers in a game is 18% 18 \% , what is the probability that the Islanders will win exactly one out of six games in a series against the Rangers? Round your answer to the nearest thousandth.\newlineAnswer:

Full solution

Q. If the probability that the Islanders will beat the Rangers in a game is 18% 18 \% , what is the probability that the Islanders will win exactly one out of six games in a series against the Rangers? Round your answer to the nearest thousandth.\newlineAnswer:
  1. Identify Formula and Values: Identify the binomial probability formula and the values of nn, kk, and pp. The binomial probability formula is P(X=k)=C(n,k)(p)k(1p)(nk)P(X = k) = C(n, k) \cdot (p)^k \cdot (1-p)^{(n-k)}, where: - nn is the number of trials, - kk is the number of successes, - pp is the probability of success on a single trial. For this problem: n=6n = 6 (since there are six games), k=1k = 1 (since we want to find the probability of exactly one win), p=0.18p = 0.18 (since the probability of the Islanders winning a game is 1818%).
  2. Calculate Binomial Coefficient: Calculate the binomial coefficient C(n,k)C(n, k). The binomial coefficient C(n,k)C(n, k) is calculated using the formula n!k!(nk)!\frac{n!}{k!(n - k)!}. For n=6n = 6 and k=1k = 1, we have: C(6,1)=6!1!(61)!=61×5!=6120=120=0.05C(6, 1) = \frac{6!}{1!(6 - 1)!} = \frac{6}{1 \times 5!} = \frac{6}{120} = \frac{1}{20} = 0.05.
  3. Calculate Probability of One Win: Calculate the probability of exactly one win using the binomial probability formula.\newlineSubstitute n=6n = 6, k=1k = 1, and p=0.18p = 0.18 into the formula P(X=k)=C(n,k)(p)k(1p)(nk)P(X = k) = C(n, k) \cdot (p)^k \cdot (1 - p)^{(n - k)}:\newlineP(X=1)=C(6,1)(0.18)1(10.18)(61)P(X = 1) = C(6, 1) \cdot (0.18)^1 \cdot (1 - 0.18)^{(6 - 1)}.
  4. Solve Probability Expression: Solve the probability expression.\newlineFirst, calculate (0.18)1(0.18)^1, which is simply 0.180.18.\newlineNext, calculate (10.18)(61)(1 - 0.18)^{(6 - 1)}, which is (0.82)5(0.82)^5.\newline(0.82)5=0.82×0.82×0.82×0.82×0.820.32890368(0.82)^5 = 0.82 \times 0.82 \times 0.82 \times 0.82 \times 0.82 \approx 0.32890368.\newlineNow, multiply C(6,1)C(6, 1), (0.18)1(0.18)^1, and (0.82)5(0.82)^5 together:\newlineP(X=1)=0.05×0.18×0.328903680.00296553P(X = 1) = 0.05 \times 0.18 \times 0.32890368 \approx 0.00296553.
  5. Round to Nearest Thousandth: Round the answer to the nearest thousandth.\newlineP(X=1)0.00296553P(X = 1) \approx 0.00296553 rounded to the nearest thousandth is 0.0030.003.

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