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If Q13P=30Q-\dfrac{1}{3}P=30, which of the following correctly gives PP in terms of QQ?

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Q. If Q13P=30Q-\dfrac{1}{3}P=30, which of the following correctly gives PP in terms of QQ?
  1. Isolate P term: We are given the equation Q13P=30Q - \frac{1}{3}P = 30 and we need to solve for PP in terms of QQ.\newlineFirst, we will isolate the term containing PP on one side of the equation.\newlineAdd 13P\frac{1}{3}P to both sides of the equation to move the term with PP to the right side.\newlineQ13P+13P=30+13PQ - \frac{1}{3}P + \frac{1}{3}P = 30 + \frac{1}{3}P
  2. Simplify left side: Now, we simplify the left side of the equation by combining like terms. \newlineQ+0=30+(13)PQ + 0 = 30 + (\frac{1}{3})P\newlineThis simplifies to:\newlineQ=30+(13)PQ = 30 + (\frac{1}{3})P
  3. Isolate P: Next, we need to isolate P. To do this, we subtract 3030 from both sides of the equation.\newlineQ30=(13)PQ - 30 = (\frac{1}{3})P
  4. Multiply by 33: Finally, to solve for PP, we multiply both sides of the equation by 33 to get rid of the fraction.\newline3(Q30)=P3(Q - 30) = P
  5. Distribute 33: Now, we distribute the 33 on the left side of the equation.3Q90=P3Q - 90 = P
  6. Express PP in terms of QQ: We have now expressed PP in terms of QQ.P=3Q90P = 3Q - 90

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