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if g(x)=2x2+x g(x)=2x^2+x what is the value of g(12) g(\frac{1}{2})

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Full solution

Q. if g(x)=2x2+x g(x)=2x^2+x what is the value of g(12) g(\frac{1}{2})
  1. Substitute x=12x = \frac{1}{2}: Substitute x=12x = \frac{1}{2} into the function g(x)=2x2+xg(x) = 2x^2 + x.g(12)=2(12)2+(12)g\left(\frac{1}{2}\right) = 2\left(\frac{1}{2}\right)^2 + \left(\frac{1}{2}\right)
  2. Calculate square of 12\frac{1}{2}: Calculate the square of 12\frac{1}{2}.(12)2=14\left(\frac{1}{2}\right)^2 = \frac{1}{4}
  3. Multiply by 22: Multiply 22 by the result from Step 22.\newline2×(14)=122 \times \left(\frac{1}{4}\right) = \frac{1}{2}
  4. Add to 12\frac{1}{2}: Add the result from Step 33 to 12\frac{1}{2}.12+12=1\frac{1}{2} + \frac{1}{2} = 1

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