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If
f(x)=7^(4x)-11, what is the value of
f(1), to the nearest ten-thousandth (if necessary)?
Answer:

If $f(x)=7^{4 x}-11$ , what is the value of $f(1)$ , to the nearest ten-thousandth (if necessary)? $\newline$ Answer:

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Solve exponential equations using logarithms

Full solution

Q. If

f(x)=7^{4 x}-11

, what is the value of

f(1)

, to the nearest ten-thousandth (if necessary)?

\newline

Answer:

Substitute $x$ with $1$ : To find the value of $f(1)$ , we need to substitute $x$ with $1$ in the function $f(x) = 7^{4x} - 11$ .
$f(1) = 7^{4\times 1} - 11$
$f(1) = 7^4 - 11$
Calculate $7^4$ : Now we calculate $7^4$ , which is $7$ multiplied by itself $4$ times. $\newline$ $7^4 = 7 \times 7 \times 7 \times 7$ $\newline$ $7^4 = 2401$
Subtract $11$ : Subtract $11$ from $2401$ to get the value of $f(1)$ . $\newline$ $f(1) = 2401 - 11$ $\newline$ $f(1) = 2390$
No rounding needed: The question asks for the answer to the nearest ten-thousandth, but since our result is an integer, no rounding is necessary. $\newline$ $f(1) = 2390$

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