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If f(x+2)=g1(x+1)f(x+2)=g^{-1}(x+1) value of fg(1)=?f \circ g (1) = ?

Full solution

Q. If f(x+2)=g1(x+1)f(x+2)=g^{-1}(x+1) value of fg(1)=?f \circ g (1) = ?
  1. Find g(1)g(1): First, we need to find g(1)g(1) since we're looking for f(g(1))f(g(1)).
  2. Use f(x+2)=g1(x+1)f(x+2) = g^{-1}(x+1): Since we don't have g(x)g(x) directly, we use the given f(x+2)=g1(x+1)f(x+2) = g^{-1}(x+1). This means g1(1+1)g^{-1}(1+1) should give us the x+2x+2 that we can plug into ff.
  3. Stuck at g(1)g(1): So, g1(2)=x+2g^{-1}(2) = x+2. But we need g(1)g(1), not g1(2)g^{-1}(2). We're kinda stuck here, aren't we?

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