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If f(1)=8 and f(n+1)=5f(n)-1 then find the value of f(5). Answer:

If f(1)=8 f(1)=8 and f(n+1)=5f(n)−1 f(n+1)=5 f(n)-1 then find the value of f(5) f(5) .\newlineAnswer:

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Q. If f(1)=8 f(1)=8 and f(n+1)=5f(n)−1 f(n+1)=5 f(n)-1 then find the value of f(5) f(5) .\newlineAnswer:
  1. Find f(2)f(2): We are given that f(1)=8f(1) = 8. We need to find f(5)f(5) using the recursive formula f(n+1)=5f(n)−1f(n+1) = 5f(n) - 1. Let's start by finding f(2)f(2).\newlinef(2)=5f(1)−1f(2) = 5f(1) - 1\newlinef(2)=5(8)−1f(2) = 5(8) - 1\newlinef(2)=40−1f(2) = 40 - 1\newlinef(2)=39f(2) = 39
  2. Find f(3)f(3): Now that we have f(2)f(2), we can find f(3)f(3) using the same recursive formula.\newlinef(3)=5f(2)−1f(3) = 5f(2) - 1\newlinef(3)=5(39)−1f(3) = 5(39) - 1\newlinef(3)=195−1f(3) = 195 - 1\newlinef(3)=194f(3) = 194
  3. Calculate f(4)f(4): Next, we calculate f(4)f(4) using the value of f(3)f(3).
    f(4)=5f(3)−1f(4) = 5f(3) - 1
    f(4)=5(194)−1f(4) = 5(194) - 1
    f(4)=970−1f(4) = 970 - 1
    f(4)=969f(4) = 969
  4. Find f(5)f(5): Finally, we find f(5)f(5) using the value of f(4)f(4).
    f(5)=5f(4)−1f(5) = 5f(4) - 1
    f(5)=5(969)−1f(5) = 5(969) - 1
    f(5)=4845−1f(5) = 4845 - 1
    f(5)=4844f(5) = 4844

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