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If a fair die is rolled 6 times, what is the probability, to the nearest thousandth, of getting exactly o ones?
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If a fair die is rolled 66 times, what is the probability, to the nearest thousandth, of getting exactly o ones?\newlineAnswer:

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Q. If a fair die is rolled 66 times, what is the probability, to the nearest thousandth, of getting exactly o ones?\newlineAnswer:
  1. Understand the problem: Understand the problem.\newlineWe need to calculate the probability of not rolling a one on a six-sided die in each of 66 trials. A fair six-sided die has an equal chance of landing on any of its faces, which means the probability of not rolling a one in a single trial is 56\frac{5}{6}, since there are 55 other outcomes that are not one.
  2. Calculate probabilities: Calculate the probability of not rolling a one in each of the 66 trials.\newlineSince each roll is independent, we multiply the probability of the event not happening in a single trial by itself 66 times to find the probability of it not happening in 66 trials. This is (5/6)(5/6) raised to the power of 66.
  3. Perform the calculation: Perform the calculation.\newline(56)6=(5666)=15625466560.3349(\frac{5}{6})^6 = (\frac{5^6}{6^6}) = \frac{15625}{46656} \approx 0.3349 when rounded to the nearest thousandth.
  4. Verify the calculation: Verify the calculation.\newlineWe can verify the calculation by ensuring that the base and the exponent were correctly applied in the calculation and that the rounding was done to the nearest thousandth.