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If 
(1)/(6)sqrtk-3=1-sqrtk, approximately what is the value of 
k ?
Choose 1 answer:
(A) 1.9
(B) 2.9
(C) 3.4
(D) 11.8

If 16k3=1k \frac{1}{6} \sqrt{k}-3=1-\sqrt{k} , approximately what is the value of k k ?\newlineChoose 11 answer:\newline(A) 11.99\newline(B) 22.99\newline(C) 33.44\newline(D) 1111.88

Full solution

Q. If 16k3=1k \frac{1}{6} \sqrt{k}-3=1-\sqrt{k} , approximately what is the value of k k ?\newlineChoose 11 answer:\newline(A) 11.99\newline(B) 22.99\newline(C) 33.44\newline(D) 1111.88
  1. Rewrite Equation: Rewrite the equation to isolate the square root terms on one side: \newline(\frac{\(1\)}{\(6\)})\sqrt{k} - \(3 + \sqrt{k} = 11
  2. Combine Like Terms: Combine like terms: 16k+k=1+3\frac{1}{6}\sqrt{k} + \sqrt{k} = 1 + 3
  3. Find Common Denominator: Find a common denominator for the square root terms:\newline16k+66k=4\frac{1}{6}\sqrt{k} + \frac{6}{6}\sqrt{k} = 4
  4. Add Fractions: Add the fractions: (1+6)/(6)k=4(1+6)/(6)\sqrt{k} = 4
  5. \newline \newline
  6. Multiply Both Sides: Multiply both sides by 67\frac{6}{7} to isolate k\sqrt{k}:k=4×67\sqrt{k} = \frac{4 \times 6}{7}
  7. Calculate Right Side: Calculate the right side: k=247\sqrt{k} = \frac{24}{7}
  8. Square Both Sides: Square both sides to solve for kk:k=(247)2k = \left(\frac{24}{7}\right)^2
  9. Calculate Square: Calculate the square:\newlinek=24272k = \frac{24^2}{7^2}\newlinek=57649k = \frac{576}{49}
  10. Simplify Fraction: Simplify the fraction to find the approximate value of kk:k11.755k \approx 11.755
  11. Round Value: Round the value of kk to one decimal place to match the answer choices: k11.8k \approx 11.8

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