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Identify whether the equation below has one solution, no solutions or an infinite number of solutions. Explain your answer. 3(4x-5)=6x+15

Identify whether the equation below has one solution, no solutions or an infinite number of solutions. Explain your answer.\newline3(4x−5)=6x+15 3(4 x-5)=6 x+15

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Full solution

Q. Identify whether the equation below has one solution, no solutions or an infinite number of solutions. Explain your answer.\newline3(4x−5)=6x+15 3(4 x-5)=6 x+15
  1. Distribute 33: Step 11: Distribute the 33 into the parentheses.\newlineCalculation: 3(4x)−3(5)=12x−153(4x) - 3(5) = 12x - 15
  2. Combine Like Terms: Step 22: Bring all terms involving xx to one side and constant terms to the other side.\newlineCalculation: 12x−15=6x+1512x - 15 = 6x + 15\newline12x−6x=15+1512x - 6x = 15 + 15\newline6x=306x = 30
  3. Solve for x: Step 33: Solve for x.\newlineCalculation: x=306x = \frac{30}{6}\newlinex=5x = 5

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