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Identify the properties used.

2y=

y=

qquad

qquad 4
4.
(n)/(4)-2=10

(n)/(4)=

qquad

qquad

n=

qquad

Identify the properties used. $\newline$ $2 y=$ $\newline$ $y=$ $\newline$ $\qquad$ $\newline$ $\qquad$ $4$ $\newline$ $4$ . $\frac{n}{4}-2=10$ $\newline$ $\frac{n}{4}=$ $\newline$ $\qquad$ $\newline$ $\qquad$ $\newline$ $n=$ $\newline$ $\qquad$

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Solve multi-step equations with fractional coefficients

Full solution

Q. Identify the properties used.

\newline

2 y=

\newline

y=

\newline

\qquad

\newline

\qquad

4

\newline

4

.

\frac{n}{4}-2=10

\newline

\frac{n}{4}=

\newline

\qquad

\newline

\qquad

\newline

n=

\newline

\qquad

Apply Transitive Property: First, let's look at the expression $2y = y = 4$ . This uses the Transitive Property of Equality, which states if $a = b$ and $b = c$ , then $a = c$ . So if $2y = 4$ and $y = 4$ , then $2y = y$ .
Solve for y: Now let's solve for y. If $2y = 4$ , then $y = 4 / 2$ , which means $y = 2$ .
Isolate n term: Next, we have $(n)/(4) - 2 = 10$ . To solve for n, first add $2$ to both sides to isolate the term with n. So, $(n)/(4) - 2 + 2 = 10 + 2$ , which gives us $(n)/(4) = 12$ .
Multiply to solve for n: Now, multiply both sides by $4$ to solve for $n$ . So, $\frac{n}{4} \times 4 = 12 \times 4$ , which means $n = 48$ .

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