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Let’s check out your problem:
Identify the center and radius.
\newline
(
x
−
6
)
2
+
(
y
−
1
)
2
=
9
(x-6)^{2}+(y-1)^{2}=9
(
x
−
6
)
2
+
(
y
−
1
)
2
=
9
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Math Problems
Precalculus
Find the magnitude of a vector
Full solution
Q.
Identify the center and radius.
\newline
(
x
−
6
)
2
+
(
y
−
1
)
2
=
9
(x-6)^{2}+(y-1)^{2}=9
(
x
−
6
)
2
+
(
y
−
1
)
2
=
9
Recognize standard form:
Recognize the standard form of a circle's equation, which is
(
x
−
h
)
2
+
(
y
−
k
)
2
=
r
2
(x-h)^2 + (y-k)^2 = r^2
(
x
−
h
)
2
+
(
y
−
k
)
2
=
r
2
, where
(
h
,
k
)
(h, k)
(
h
,
k
)
is the center and
r
r
r
is the radius.
Compare given equation:
Compare the given equation
x
−
6
)
2
+
(
y
−
1
)
2
=
9
w
i
t
h
t
h
e
s
t
a
n
d
a
r
d
f
o
r
m
.
I
d
e
n
t
i
f
y
$
h
=
6
x-6)^2 + (y-1)^2 = 9\ with the standard form. Identify \$h=6
x
−
6
)
2
+
(
y
−
1
)
2
=
9
w
i
t
h
t
h
es
t
an
d
a
r
df
or
m
.
I
d
e
n
t
i
f
y
$
h
=
6
,
k
=
1
k=1
k
=
1
, and
r
2
=
9
r^2=9
r
2
=
9
.
Calculate radius:
Calculate the radius
r
r
r
by taking the
square root
of
9
9
9
.
r
=
9
=
3
r = \sqrt{9} = 3
r
=
9
=
3
.
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Question
Find the value of
x
x
x
that solves the equation
ln
(
x
−
1
)
=
2
−
ln
2
\ln (x-1)=2-\ln 2
ln
(
x
−
1
)
=
2
−
ln
2
.
\newline
Answer:
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Click and drag like terms onto each other to simplify fully.
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Click and drag like terms onto each other to simplify fully.
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Click and drag like terms onto each other to simplify fully.
\newline
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y
=
x
(
x
−
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)
(
x
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y = x(x - 3)(x - 2)
y
=
x
(
x
−
3
)
(
x
−
2
)
what is the value of
y
y
y
when
x
=
3
x = 3
x
=
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?
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Posted 1 year ago
Question
For the following set of data, find the sample standard deviation, to the nearest hundredth.
\newline
146
,
147
,
144
,
117
,
105
,
105
,
89
146,147,144,117,105,105,89
146
,
147
,
144
,
117
,
105
,
105
,
89
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Posted 11 months ago
Question
The length of a rectangle's diagonal is
2
29
2 \sqrt{29}
2
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10
10
10
. What is the area of the rectangle?
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Posted 1 year ago
Question
What is the volume of a square-based pyramid with base side length of
8
8
8
inches and a height of
12
12
12
inches? Write your answer in the box provided.
\newline
_
_
_
_
_
in
3
.
\_\_\_\_\_ \text{in}^{3}.
_____
in
3
.
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Posted 11 months ago
Question
Evaluate the expression
8
d
\frac{8}{d}
d
8
when
d
=
4
d=4
d
=
4
.
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Posted 11 months ago
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