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Identify the amplitude and period of the following function.

f(theta)=10 sin((pi theta)/(10))

Identify the amplitude and period of the following function.\newlinef(θ)=10sin(πθ10) f(\theta)=10 \sin \left(\frac{\pi \theta}{10}\right)

Full solution

Q. Identify the amplitude and period of the following function.\newlinef(θ)=10sin(πθ10) f(\theta)=10 \sin \left(\frac{\pi \theta}{10}\right)
  1. Identify Function Form: Identify the general form of the function to determine amplitude and period.\newlineThe function given is f(θ)=10sin(πθ10)f(\theta) = 10 \sin\left(\frac{\pi \theta}{10}\right). This matches the general sine function form Asin(Bx)A \sin(Bx), where AA is the amplitude and the period is 2πB\frac{2\pi}{B}.
  2. Calculate Amplitude: Calculate the amplitude. The amplitude AA is the coefficient before the sine function, which is 1010.
  3. Calculate Period: Calculate the period.\newlineThe period formula is 2π/B2\pi/B, where BB is the coefficient of θ\theta inside the sine function. Here, B=(π/10)B = (\pi/10). So, the period is 2π/(π/10)=202\pi / (\pi/10) = 20.

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