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How would you write the equation with a slope of 
2//3 and a 
y-intercept of -3
a) 
y=3//2x+3
b) 
y=2//3-3
c) 
y=2//3x+3
d) 
y=2//3x-3

33. How would you write the equation with a slope of 2/3 2 / 3 and a y y -intercept of 3-3\newlinea) y=3/2x+3 y=3 / 2 x+3 \newlineb) y=2/33 y=2 / 3-3 \newlinec) y=2/3x+3 y=2 / 3 x+3 \newlined) y=2/3x3 y=2 / 3 x-3

Full solution

Q. 33. How would you write the equation with a slope of 2/3 2 / 3 and a y y -intercept of 3-3\newlinea) y=3/2x+3 y=3 / 2 x+3 \newlineb) y=2/33 y=2 / 3-3 \newlinec) y=2/3x+3 y=2 / 3 x+3 \newlined) y=2/3x3 y=2 / 3 x-3
  1. Slope-intercept form: Slope-intercept form is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
  2. Plug in values: Plug in the given slope (23)(\frac{2}{3}) for mm and the y-intercept (3)(-3) for bb into the slope-intercept form.\newlineCalculation: y=(23)x+(3)y = (\frac{2}{3})x + (-3)
  3. Simplify equation: Simplify the equation to get the final form.\newlineCalculation: y=23x3y = \frac{2}{3}x - 3

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