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how to graph 2sin(12(x+π3))+12\sin\left(\frac{1}{2}(x+\frac{\pi}{3})\right)+1

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Q. how to graph 2sin(12(x+π3))+12\sin\left(\frac{1}{2}(x+\frac{\pi}{3})\right)+1
  1. Understand Sine Function Form: First, we need to understand the general form of the sine function, which is y=Asin(B(xC))+Dy = A\sin(B(x - C)) + D, where AA is the amplitude, BB affects the period, CC is the phase shift, and DD is the vertical shift. In our function, 2sin(12(x+π3))+12\sin(\frac{1}{2}(x+\frac{\pi}{3}))+1, A=2A = 2, B=12B = \frac{1}{2}, C=π3C = -\frac{\pi}{3}, and D=1D = 1. We will use these values to graph the function.
  2. Calculate Period: Next, we calculate the period of the function. The period of a sine function is given by 2π/B2\pi/B. In our case, B=1/2B = 1/2, so the period TT is 2π/(1/2)=4π2\pi/(1/2) = 4\pi.
  3. Determine Phase Shift: Now, we determine the phase shift. The phase shift is given by the value of CC in the general form, which is subtracted from xx. In our function, C=π3C = -\frac{\pi}{3}, so the phase shift is to the left by π3\frac{\pi}{3} units.
  4. Consider Vertical Shift: We also need to consider the vertical shift, which is DD in the general form. In our function, D=1D = 1, so the graph will be shifted up by 11 unit.
  5. Graph Function: To graph the function, we start by drawing the basic sine curve, then apply the transformations. We'll plot key points for one period of the sine function, starting at the phase shift. The key points occur at 00, T/4T/4, T/2T/2, 3T/43T/4, and TT, where TT is the period. We'll then shift these points left by π/3\pi/3 units and up by 11 unit.
  6. Determine Amplitude: The amplitude of the function is 22, which means the maximum value is 22 units above the midline (y=1y = 1), and the minimum value is 22 units below the midline (y=1y = 1). So, the maximum and minimum values of the function are 33 and 1-1, respectively.
  7. Plot Key Points: Plot the points for one period: starting at the phase shift x=π3x = -\frac{\pi}{3}, the sine function starts at the midline, reaches its maximum at x=π3+T4x = -\frac{\pi}{3} + \frac{T}{4}, crosses the midline again at x=π3+T2x = -\frac{\pi}{3} + \frac{T}{2}, reaches its minimum at x=π3+3T4x = -\frac{\pi}{3} + \frac{3T}{4}, and returns to the midline at x=π3+Tx = -\frac{\pi}{3} + T. Adjust these xx-values by the phase shift and yy-values by the vertical shift.
  8. Connect Points: Connect the points with a smooth, continuous curve, making sure the curve has the shape of a sine wave, with the appropriate maximum and minimum values and crossing the midline at the correct points.

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