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How many solutions does this equation have?\newline6+j=j-6 + j = -j\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions

Full solution

Q. How many solutions does this equation have?\newline6+j=j-6 + j = -j\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions
  1. Simplify equation: Simplify the equation by moving all terms involving jj to one side.6+j=j-6 + j = -jAdd jj to both sides:6+j+j=0-6 + j + j = 06+2j=0-6 + 2j = 0
  2. Add and isolate jj: Solve for jj.\newlineAdd 66 to both sides:\newline2j=62j = 6\newlineDivide both sides by 22:\newlinej=3j = 3

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