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How many solutions does this equation have?\newline−5−2j=−2j-5 - 2j = -2j\newlineChoices:\newline(A) no solution\newline(B) one solution\newline(C) infinitely many solutions

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Find the number of solutions to a linear equationright chevron icon

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Q. How many solutions does this equation have?\newline−5−2j=−2j-5 - 2j = -2j\newlineChoices:\newline(A) no solution\newline(B) one solution\newline(C) infinitely many solutions
  1. Simplify equation by isolating terms: Simplify the equation by isolating terms involving jj.−5−2j=−2j-5 - 2j = -2j Add 2j2j to both sides to eliminate jj from the right side.−5−2j+2j=−2j+2j-5 - 2j + 2j = -2j + 2j−5=0-5 = 0
  2. Add terms to eliminate jj: Analyze the simplified equation.\-5 = 0 is a false statement, indicating no value of jj can satisfy the equation.

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