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How many solutions does the system of equations below have?\newlinex2yz=3x - 2y - z = 3\newline2x+3y3z=0-2x + 3y - 3z = 0\newline2x+2y3z=12x + 2y - 3z = 1\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions

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Q. How many solutions does the system of equations below have?\newlinex2yz=3x - 2y - z = 3\newline2x+3y3z=0-2x + 3y - 3z = 0\newline2x+2y3z=12x + 2y - 3z = 1\newlineChoices:\newline(A)no solution\newline(B)one solution\newline(C)infinitely many solutions
  1. Write Equations: First, let's write down the system of equations:\newline11. x2yz=3x - 2y - z = 3\newline22. 2x+3y3z=0-2x + 3y - 3z = 0\newline33. 2x+2y3z=12x + 2y - 3z = 1
  2. Eliminate x: Now, let's add equations 11 and 22 to eliminate x:\newline(1)+(2)(1) + (2) gives us:\newlinex2yz2x+3y3z=3+0x - 2y - z - 2x + 3y - 3z = 3 + 0\newlinex+y4z=3-x + y - 4z = 3
  3. Eliminate x Again: Next, let's add equations 11 and 33 to eliminate x:\newline(1)+(3)(1) + (3) gives us:\newlinex2yz+2x+2y3z=3+1x - 2y - z + 2x + 2y - 3z = 3 + 1\newline3x4z=43x - 4z = 4
  4. Eliminate y: Now, let's multiply the new equation from step 33 by 22 and add it to the new equation from step 44 to eliminate yy: \newline2(x+y4z)+(3x4z)=2(3)+42(-x + y - 4z) + (3x - 4z) = 2(3) + 4 \newline2x+2y8z+3x4z=6+4-2x + 2y - 8z + 3x - 4z = 6 + 4 \newlinex12z=10x - 12z = 10

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