How many pounds of candy that sells for $3.25 per lb must be mixed with candy that sells for $2.75 per lb to obtain 20lb of a mixture that should sell for $3.15 per lb ?□ Ib of $3.25-per-lb candy must be mixed with □ Ib of $2.75-per-lb candy. (Type integers or decimals.)
Q. How many pounds of candy that sells for $3.25 per lb must be mixed with candy that sells for $2.75 per lb to obtain 20lb of a mixture that should sell for $3.15 per lb ?□ Ib of $3.25-per-lb candy must be mixed with □ Ib of $2.75-per-lb candy. (Type integers or decimals.)
Define Variables: Let x be the amount of $3.25-per-lb candy, and (20−x) be the amount of $2.75-per-lb candy.
Set Up Equation: Set up the equation: 3.25x+2.75(20−x)=3.15×20.
Simplify Equation: Simplify the equation: 3.25x+55−2.75x=63.
Combine Like Terms: Combine like terms: 0.5x+55=63.
Subtract 55: Subtract 55 from both sides: 0.5x=8.
Divide by 0.5: Divide both sides by 0.5 to find x: x=0.58.
Calculate x: Calculate x: x=16.
Find $2.75 Candy: Find the amount of $2.75-per-lb candy: 20−x=20−16.
Calculate $2.75 Candy: Calculate the amount of $2.75-per-lb candy: 20−16=4.
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