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How many pounds of candy that sells for $\$ 3.25$ per lb must be mixed with candy that sells for $\$ 2.75 \mathrm{per} \mathrm{lb}$ to obtain $10 \mathrm{lb}$ of a mixture that should sell for $\$ 2.90$ per $\mathrm{lb}$ ?$\newline$$\square$ Ib of $\$ 3.25$-per-lb candy must be mixed with $\square$ Ib of $\$ 2.75$-per-lb candy.$\newline$(Type integers or decimals.)