How many pounds of candy that sells for $3.25 per lb must be mixed with candy that sells for $1.75 per lb to obtain 20lb of a mixture that should sell for $2.50 per lb?□ Ib of $3.25-per-lb candy must be mixed with □ Ib of $1.75-per-lb candy. (Type integers or decimals.)
Q. How many pounds of candy that sells for $3.25 per lb must be mixed with candy that sells for $1.75 per lb to obtain 20lb of a mixture that should sell for $2.50 per lb?□ Ib of $3.25-per-lb candy must be mixed with □ Ib of $1.75-per-lb candy. (Type integers or decimals.)
Define variables: Let x be the pounds of $3.25-per-lb candy, and (20−x) be the pounds of $1.75-per-lb candy.
Set up equation: Set up the equation based on the total cost of the mixture: 3.25x+1.75(20−x)=2.50×20.
Distribute and simplify: Distribute and simplify the equation: 3.25x+35−1.75x=50.
Combine like terms: Combine like terms: 1.5x+35=50.
Subtract 35: Subtract 35 from both sides: 1.5x=15.
Divide by 1.5: Divide both sides by 1.5 to solve for x: x=1.515.
Calculate x: Calculate x: x=10.
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