How many pounds of candy that sells for $2.75 per lb must be mixed with candy that sells for $1.25 per lb to obtain 10lb of a mixture that should sell for $2.45 per Ib?□ Ib of $2.75-per-lb candy must be mixed with □ Ib of $1.25-per-lb candy.(Type integers or decimals.)
Q. How many pounds of candy that sells for $2.75 per lb must be mixed with candy that sells for $1.25 per lb to obtain 10lb of a mixture that should sell for $2.45 per Ib?□ Ib of $2.75-per-lb candy must be mixed with □ Ib of $1.25-per-lb candy.(Type integers or decimals.)
Define variables: Let x be the amount of $2.75-per-lb candy, and (10−x) be the amount of $1.25-per-lb candy.
Set up equation: Set up the equation: 2.75x+1.25(10−x)=2.45×10.
Combine terms: Distribute and combine like terms: 2.75x+12.5−1.25x=24.5.
Solve for x: Combine x terms: 1.5x+12.5=24.5.
Substitute x: Subtract 12.5 from both sides: 1.5x=12.
Substitute x: Subtract 12.5 from both sides: 1.5x=12.Divide both sides by 1.5 to solve for x: x=1.512.
Substitute x: Subtract 12.5 from both sides: 1.5x=12.Divide both sides by 1.5 to solve for x: x=1.512.Calculate x: x=8.
Substitute x: Subtract 12.5 from both sides: 1.5x=12.Divide both sides by 1.5 to solve for x: x=1.512.Calculate x: x=8.Substitute x back into (10−x) to find the amount of 12.50-per-lb candy: 12.51.