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How many moles of hydrogen, HH, are needed to react with 3.03.0 moles of nitrogen, N2N_2?

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Q. How many moles of hydrogen, HH, are needed to react with 3.03.0 moles of nitrogen, N2N_2?
  1. Chemical Equation: The balanced chemical equation for the reaction between nitrogen and hydrogen to form ammonia is N2+3H22NH3\mathrm{N}_2 + 3\mathrm{H}_2 \rightarrow 2\mathrm{NH}_3.
  2. Moles Ratio: According to the equation, 11 mole of nitrogen reacts with 33 moles of hydrogen.
  3. Moles Calculation: So, if we have 3.03.0 moles of nitrogen, we need 33 times as much hydrogen.
  4. Moles Calculation: So, if we have 3.03.0 moles of nitrogen, we need 33 times as much hydrogen.Calculate the moles of hydrogen needed: 3.03.0 moles N2×3\text{N}_2 \times 3 moles H2/moleN2=9.0\text{H}_2/\text{mole} \text{N}_2 = 9.0 moles $\text{H}_2.

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