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How many groups of $\frac{3}{8}$ are in $1$ ?

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Operations with rational exponents

Full solution

Q. How many groups of

\frac{3}{8}

are in

1

?

Divide by $3$ / $8$ : To find out how many groups of $3/8$ are in $1$ , we divide $1$ by $3/8$ . $1 \div (3/8) = 1 \times (8/3) = 8/3$
Simplify $\frac{8}{3}$ : Now, simplify $\frac{8}{3}$ . $\frac{8}{3} = 2$ with a remainder of $2$ , so $\frac{8}{3} = 2 \frac{2}{3}$ .
Final Result: So, there are $2\frac{2}{3}$ groups of $\frac{3}{8}$ in $1$ .

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