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How does h(x)=10xh(x) = 10^x change over the interval from x=5x = 5 to x=6x = 6?\newlineChoices:\newline(A) h(x)h(x) increases by 10%10\%\newline(B) h(x)h(x) increases by 900%900\%\newline(C) h(x)h(x) increases by 1010\newline(D) h(x)h(x) decreases by 1010

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Q. How does h(x)=10xh(x) = 10^x change over the interval from x=5x = 5 to x=6x = 6?\newlineChoices:\newline(A) h(x)h(x) increases by 10%10\%\newline(B) h(x)h(x) increases by 900%900\%\newline(C) h(x)h(x) increases by 1010\newline(D) h(x)h(x) decreases by 1010
  1. Calculate h(6)h(6): Now, calculate h(6)h(6) which is 10610^6.\newlineh(6)=106=1,000,000.h(6) = 10^6 = 1,000,000.
  2. Find increase: Find the increase from h(5)h(5) to h(6)h(6).\newlineIncrease = h(6)h(5)=1,000,000100,000=900,000h(6) - h(5) = 1,000,000 - 100,000 = 900,000.
  3. Determine percentage increase: Determine the percentage increase.\newlinePercentage increase = (Increase/h(5))×100%(\text{Increase} / h(5)) \times 100\% = (900,000/100,000)×100%(900,000 / 100,000) \times 100\% = 900%900\%.

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