Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

How does h(t)=2th(t) = 2^t change over the interval from t=7t = 7 to t=8t = 8?\newlineChoices:\newline(A) h(t)h(t) decreases by a factor of 22\newline(B) h(t)h(t) decreases by 22\newline(C) h(t)h(t) increases by a factor of 22\newline(D) h(t)h(t) increases by t=7t = 700

Full solution

Q. How does h(t)=2th(t) = 2^t change over the interval from t=7t = 7 to t=8t = 8?\newlineChoices:\newline(A) h(t)h(t) decreases by a factor of 22\newline(B) h(t)h(t) decreases by 22\newline(C) h(t)h(t) increases by a factor of 22\newline(D) h(t)h(t) increases by t=7t = 700
  1. Calculate h(t)h(t): Calculate h(t)h(t) when t=7t = 7.\newlineh(7)=27h(7) = 2^7\newlineh(7)=128h(7) = 128
  2. Calculate h(t)h(t): Calculate h(t)h(t) when t=8t = 8.
    h(8)=28h(8) = 2^8
    h(8)=256h(8) = 256
  3. Compare h(7)h(7) and h(8)h(8): Compare h(7)h(7) and h(8)h(8) to determine the change.h(8)h(8) is twice h(7)h(7), so h(t)h(t) increases by a factor of 22 from t=7t = 7 to t=8t = 8.

More problems from Interpreting Linear Expressions