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How does g(x)=5xg(x) = 5^x change over the interval from x=9x = 9 to x=10x = 10?\newlineChoices:\newline(A) g(x)g(x) increases by 55\newline(B) g(x)g(x) increases by a factor of 55\newline(C) g(x)g(x) decreases by a factor of 55\newline(D) g(x)g(x) increases by x=9x = 900

Full solution

Q. How does g(x)=5xg(x) = 5^x change over the interval from x=9x = 9 to x=10x = 10?\newlineChoices:\newline(A) g(x)g(x) increases by 55\newline(B) g(x)g(x) increases by a factor of 55\newline(C) g(x)g(x) decreases by a factor of 55\newline(D) g(x)g(x) increases by x=9x = 900
  1. Calculate g(9)g(9): Calculate g(9)g(9) by substituting x=9x = 9 into g(x)=5xg(x) = 5^x.\newlineg(9)=59g(9) = 5^9
  2. Calculate g(10)g(10): Calculate g(10)g(10) by substituting x=10x = 10 into g(x)=5xg(x) = 5^x.\newlineg(10)=510g(10) = 5^{10}
  3. Compare g(9)g(9) and g(10)g(10): Compare g(9)g(9) and g(10)g(10) to determine the change.\newlineSince 5105^{10} is 55 times larger than 595^{9}, g(x)g(x) increases by a factor of 55 from x=9x = 9 to g(10)g(10)00.
  4. Choose the correct answer: Choose the correct answer from the given choices.\newlineThe correct choice is (B) g(x)g(x) increases by a factor of 55.

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