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How does g(t)=7tg(t) = 7^t change over the interval from t=5t = 5 to t=6t = 6?\newlineChoices:\newline(A) g(t)g(t) decreases by 7%7\%\newline(B) g(t)g(t) increases by 77\newline(C) g(t)g(t) increases by 7%7\%\newline(D) g(t)g(t) increases by a factor of 77

Full solution

Q. How does g(t)=7tg(t) = 7^t change over the interval from t=5t = 5 to t=6t = 6?\newlineChoices:\newline(A) g(t)g(t) decreases by 7%7\%\newline(B) g(t)g(t) increases by 77\newline(C) g(t)g(t) increases by 7%7\%\newline(D) g(t)g(t) increases by a factor of 77
  1. Calculate g(5)g(5): Calculate g(5)g(5) by plugging in t=5t = 5 into the function.\newlineg(5)=75g(5) = 7^5
  2. Calculate g(6)g(6): Calculate g(6)g(6) by plugging in t=6t = 6 into the function.\newlineg(6)=76g(6) = 7^6
  3. Find factor of increase: Find the factor of increase from g(5)g(5) to g(6)g(6).\newlineFactor of increase = g(6)g(5)=7675\frac{g(6)}{g(5)} = \frac{7^6}{7^5}
  4. Simplify factor of increase: Simplify the factor of increase.\newlineFactor of increase = 7(65)=71=77^{(6-5)} = 7^1 = 7
  5. Determine correct choice: Determine the correct choice based on the factor of increase.\newlineSince g(t)g(t) increases by a factor of 77, the correct choice is (D) g(t)g(t) increases by a factor of 77.

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