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Home wouk

(3+sqrt7)(4-sqrt13)

Home wouk $\newline$ $(3+\sqrt{7})(4-\sqrt{13})$

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Multiply radical expressions

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Q. Home wouk

\newline

(3+\sqrt{7})(4-\sqrt{13})

Apply Distributive Property: First, we'll use the distributive property (FOIL method) to multiply the two binomials. $\newline$ $(3 + \sqrt{7}) \times (4 - \sqrt{13}) = 3\times4 + 3\times(-\sqrt{13}) + \sqrt{7}\times4 + \sqrt{7}\times(-\sqrt{13})$
Multiply the Terms: Now, let's multiply the terms. $\newline$ $3 \times 4 = 12$ $\newline$ $3 \times (-\sqrt{13}) = -3\sqrt{13}$ $\newline$ $\sqrt{7} \times 4 = 4\sqrt{7}$ $\newline$ $\sqrt{7} \times (-\sqrt{13}) = -\sqrt{7 \times 13}$
Combine Terms: Combine all the terms to get the final expression. $12 - 3\sqrt{13} + 4\sqrt{7} - \sqrt{91}$
Final Expression: There's no like terms to combine, so this is the simplest form.

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