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hboard | Rapidldentity
IXL | Compound interest |
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Liberty Hill Isd - Gal_ M Inbox (57)-jarosz.__ is: Core Ball! M 
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2065-20 Dark Royal.
iberty Hill.
My IXL
Learning
Assessment
Analytics
Eighth grade 
> 1.11 Compound interest LSK
Spencer deposited 
$10 in an account earning 
5% interest compounded annually.
To the nearest cent, how much will he have in 3 years?
Use the formula 
B=p(1+r)^(t), where 
B is the balance (final amount), 
p is the principal (starting amount), 
r is the interest rate expressed as a decimal, and 
t is the time in years.

$
Submit

hboard | Rapidldentity\newlineIXL | Compound interest |\newlineHome\newlineixl.com/math/grade8-8/compound-interest\newlineLiberty Hill Isd - Gal_ M Inbox (5757)-jarosz.__ is: Core Ball! M \quad S SHEIN Girls Letter G.\newline2065206520-20 Dark Royal.\newlineiberty Hill.\newlineMy IXL\newlineLearning\newlineAssessment\newlineAnalytics\newlineEighth grade >1.11 >1.11 Compound interest LSK\newlineSpencer deposited $10 \$ 10 in an account earning 5% 5 \% interest compounded annually.\newlineTo the nearest cent, how much will he have in 33 years?\newlineUse the formula B=p(1+r)t B=p(1+r)^{t} , where B B is the balance (final amount), p p is the principal (starting amount), r r is the interest rate expressed as a decimal, and t t is the time in years.\newline$ \$ \newlineSubmit

Full solution

Q. hboard | Rapidldentity\newlineIXL | Compound interest |\newlineHome\newlineixl.com/math/grade8-8/compound-interest\newlineLiberty Hill Isd - Gal_ M Inbox (5757)-jarosz.__ is: Core Ball! M \quad S SHEIN Girls Letter G.\newline2065206520-20 Dark Royal.\newlineiberty Hill.\newlineMy IXL\newlineLearning\newlineAssessment\newlineAnalytics\newlineEighth grade >1.11 >1.11 Compound interest LSK\newlineSpencer deposited $10 \$ 10 in an account earning 5% 5 \% interest compounded annually.\newlineTo the nearest cent, how much will he have in 33 years?\newlineUse the formula B=p(1+r)t B=p(1+r)^{t} , where B B is the balance (final amount), p p is the principal (starting amount), r r is the interest rate expressed as a decimal, and t t is the time in years.\newline$ \$ \newlineSubmit
  1. Identify Given Values: Identify the given values from the problem.\newlinePrincipal pp = $10\$10\newlineInterest rate rr = 5%5\% or 0.050.05 when expressed as a decimal\newlineTime tt = 33 years\newlineWe will use the compound interest formula B=p(1+r)tB = p(1 + r)^t to find the final balance BB.
  2. Substitute Values: Substitute the given values into the compound interest formula.\newlineB=10(1+0.05)3B = 10(1 + 0.05)^3\newlineNow we need to calculate the value inside the parentheses first, which is (1+0.05)(1 + 0.05).
  3. Calculate Inside Parentheses: Calculate the value inside the parentheses.\newline1+0.05=1.051 + 0.05 = 1.05\newlineNow we have B=10(1.05)3B = 10(1.05)^3.
  4. Calculate Exponent: Calculate the exponent part of the expression.\newline(1.05)3=1.05×1.05×1.05(1.05)^3 = 1.05 \times 1.05 \times 1.05\newlineWe need to multiply 1.051.05 by itself 33 times.
  5. Perform Multiplication: Perform the multiplication to find the value of (1.05)3(1.05)^3.1.05×1.05×1.05=1.1576251.05 \times 1.05 \times 1.05 = 1.157625Now we have B=10×1.157625B = 10 \times 1.157625.
  6. Multiply Principal: Multiply the principal by the result from Step 55 to find the final balance.\newlineB=10×1.157625B = 10 \times 1.157625\newlineB=11.57625B = 11.57625\newlineTo the nearest cent, we need to round the final balance.
  7. Round Final Balance: Round the final balance to the nearest cent.\newlineB$(11.58)B \approx \$(11.58)\newlineSpencer will have approximately $(11.58)\$(11.58) in his account after 33 years.

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