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graph g(x)=(x+5)22 g(x)=(x+5)^2-2

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Q. graph g(x)=(x+5)22 g(x)=(x+5)^2-2
  1. Identify Function: Identify the function to be graphed. The function is g(x)=(x+5)22g(x)=(x+5)^2-2, which is a quadratic function in the form of g(x)=a(xh)2+kg(x)=a(x-h)^2+k, where (h,k)(h,k) is the vertex of the parabola.
  2. Determine Vertex: Determine the vertex of the parabola. The vertex form of the quadratic function gives us the vertex directly. For g(x)=(x+5)22g(x)=(x+5)^2-2, the vertex is (5,2)(-5, -2).
  3. Analyze Direction: Analyze the direction of the parabola. Since the coefficient of the squared term (x+5)2(x+5)^2 is positive, the parabola opens upwards.
  4. Find Axis of Symmetry: Find the axis of symmetry. The axis of symmetry is a vertical line that passes through the vertex. For the function g(x)=(x+5)22g(x)=(x+5)^2-2, the axis of symmetry is x=5x=-5.
  5. Determine Y-Intercept: Determine the y-intercept. To find the y-intercept, set x=0x=0 and solve for g(x)g(x). g(0)=(0+5)22=252=23g(0)=(0+5)^2-2=25-2=23. The y-intercept is (0,23)(0, 23).
  6. Plot Points: Plot the vertex, axis of symmetry, and yy-intercept on a coordinate plane. Use these points to sketch the parabola, making sure it opens upwards and is symmetric about the axis of symmetry.

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