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Given:
Universal Set
U=1,6,8,11,12
Subset B
=6
What is the complement of Set B in Set U?

{1,6,11,12}

{1,6,8,11,12}

{1,8,11,12}

{6}

Given: $\newline$ Universal Set $\mathrm{U}=1,6,8,11,12$ $\newline$ Subset B $=6$ $\newline$ What is the complement of Set B in Set U? $\newline$ $\{1,6,11,12\}$ $\newline$ $\{1,6,8,11,12\}$ $\newline$ $\{1,8,11,12\}$ $\newline$ $\{6\}$

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Set-builder notation

Full solution

Q. Given:

\newline

Universal Set

\mathrm{U}=1,6,8,11,12

\newline

Subset B

=6

\newline

What is the complement of Set B in Set U?

\newline

\{1,6,11,12\}

\newline

\{1,6,8,11,12\}

\newline

\{1,8,11,12\}

\newline

\{6\}

Define Complement of Set $B$ : The complement of Set $B$ in Set $U$ includes all elements in $U$ that are not in $B$ .
Given Sets U and B: Set U = $\{1, 6, 8, 11, 12\}$ and Set B = $\{6\}$ .
Remove Elements of B: To find the complement, we remove the elements of $B$ from $U$ .
Complement of Set B: The complement of Set B is therefore $\{1, 8, 11, 12\}$ .

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