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Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 
0^(@) <= theta < 360^(@).

P=((3)/(5),(4)/(5))
Answer:

Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 0θ<360 0^{\circ} \leq \theta<360^{\circ} .\newlineP=(35,45) P=\left(\frac{3}{5}, \frac{4}{5}\right) \newlineAnswer:

Full solution

Q. Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 0θ<360 0^{\circ} \leq \theta<360^{\circ} .\newlineP=(35,45) P=\left(\frac{3}{5}, \frac{4}{5}\right) \newlineAnswer:
  1. Identify Coordinates: Identify the coordinates of point PP on the unit circle.\newlineThe given point PP has coordinates (x,y)=(35,45)(x, y) = (\frac{3}{5}, \frac{4}{5}). On the unit circle, these coordinates correspond to (cos(θ),sin(θ))(\cos(\theta), \sin(\theta)).
  2. Determine Reference Angle: Determine the reference angle.\newlineSince both xx and yy coordinates are positive, point PP lies in the first quadrant. The reference angle is the angle θ\theta' that the terminal side makes with the xx-axis. To find θ\theta', we use the arccosine\text{arccosine} or arcsine\text{arcsine} function. However, since we are in the first quadrant, θ\theta' is simply θ\theta.
  3. Calculate Using Arccosine: Calculate the angle using the arccosine function.\newlineWe use the x-coordinate (cos(θ)\cos(\theta)) to find the angle θ\theta. Thus, θ=arccos(35)\theta = \arccos(\frac{3}{5}). We calculate this using a calculator.
  4. Convert to Degrees: Convert the angle from radians to degrees.\newlineAfter calculating the arccosine, we get θ\theta in radians. To convert it to degrees, we multiply by 180π\frac{180}{\pi}. However, since we are using a calculator, it can directly give us the angle in degrees.
  5. Round to Nearest Tenth: Round the angle to the nearest tenth of a degree.\newlineUsing a calculator, we find that θarccos(35)53.13\theta \approx \arccos(\frac{3}{5}) \approx 53.13 degrees. Rounding to the nearest tenth of a degree, we get θ53.1\theta \approx 53.1 degrees.

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