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Given that 
f(x)=bx^(3)+5x^(2)+2x-8 and 
g(x)=bx^(3)+6x+4 has a common factor of 
x-a, where 
a is an integer, find the value of 
b.

22. Given that f(x)=bx3+5x2+2x8 \mathrm{f}(x)=b x^{3}+5 x^{2}+2 x-8 and g(x)=bx3+6x+4 \mathrm{g}(x)=b x^{3}+6 x+4 has a common factor of xa x-a , where a a is an integer, find the value of b b .

Full solution

Q. 22. Given that f(x)=bx3+5x2+2x8 \mathrm{f}(x)=b x^{3}+5 x^{2}+2 x-8 and g(x)=bx3+6x+4 \mathrm{g}(x)=b x^{3}+6 x+4 has a common factor of xa x-a , where a a is an integer, find the value of b b .
  1. Plug in x=ax=a: Since f(x)f(x) and g(x)g(x) have a common factor of xax-a, let's plug in x=ax=a into both functions and set them equal to zero.\newlinef(a)=ba3+5a2+2a8=0f(a) = ba^3 + 5a^2 + 2a - 8 = 0\newlineg(a)=ba3+6a+4=0g(a) = ba^3 + 6a + 4 = 0
  2. Subtract to eliminate bb: Subtract the second equation from the first to eliminate bb.(ba3+5a2+2a8)(ba3+6a+4)=00(ba^3 + 5a^2 + 2a - 8) - (ba^3 + 6a + 4) = 0 - 05a2+2a86a4=05a^2 + 2a - 8 - 6a - 4 = 0
  3. Simplify the equation: Simplify the equation. 5a24a12=05a^2 - 4a - 12 = 0
  4. Factor the quadratic: Factor the quadratic equation.\newline(5a+6)(a2)=0(5a + 6)(a - 2) = 0
  5. Set equal to zero: Set each factor equal to zero and solve for aa.5a+6=05a + 6 = 0 or a2=0a - 2 = 0a=65a = -\frac{6}{5} or a=2a = 2Since aa is an integer, a=2a = 2.
  6. Plug a=2a=2 back: Plug a=2a = 2 back into the equations for f(x)f(x) and g(x)g(x) to solve for bb.\newlinef(2)=2b(2)3+5(2)2+2(2)8=0f(2) = 2b(2)^3 + 5(2)^2 + 2(2) - 8 = 0\newlineg(2)=2b(2)3+6(2)+4=0g(2) = 2b(2)^3 + 6(2) + 4 = 0
  7. Simplify both equations: Simplify both equations.\newlinef(2)=16b+20+48=0f(2) = 16b + 20 + 4 - 8 = 0\newlineg(2)=16b+12+4=0g(2) = 16b + 12 + 4 = 0
  8. Solve for b: Solve for b using the equation from g(22).\newline16b+16=016b + 16 = 0\newline16b=1616b = -16\newlineb=1616b = \frac{-16}{16}\newlineb=1b = -1