Q. 2. Given that f(x)=bx3+5x2+2x−8 and g(x)=bx3+6x+4 has a common factor of x−a, where a is an integer, find the value of b.
Plug in x=a: Since f(x) and g(x) have a common factor of x−a, let's plug in x=a into both functions and set them equal to zero.f(a)=ba3+5a2+2a−8=0g(a)=ba3+6a+4=0
Subtract to eliminate b: Subtract the second equation from the first to eliminate b.(ba3+5a2+2a−8)−(ba3+6a+4)=0−05a2+2a−8−6a−4=0
Simplify the equation: Simplify the equation. 5a2−4a−12=0
Factor the quadratic: Factor the quadratic equation.(5a+6)(a−2)=0
Set equal to zero: Set each factor equal to zero and solve for a.5a+6=0 or a−2=0a=−56 or a=2Since a is an integer, a=2.
Plug a=2 back: Plug a=2 back into the equations for f(x) and g(x) to solve for b.f(2)=2b(2)3+5(2)2+2(2)−8=0g(2)=2b(2)3+6(2)+4=0
Simplify both equations: Simplify both equations.f(2)=16b+20+4−8=0g(2)=16b+12+4=0
Solve for b: Solve for b using the equation from g(2).16b+16=016b=−16b=16−16b=−1
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