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Given that events A and B are independent with 
P(A)=0.3 and 
P(B∣A)=0.89 determine the value of 
P(B), rounding to the nearest thousandth, if necessary.
Answer:

Given that events A and B are independent with P(A)=0.3 P(A)=0.3 and P(BA)=0.89 P(B \mid A)=0.89 determine the value of P(B) P(B) , rounding to the nearest thousandth, if necessary.\newlineAnswer:

Full solution

Q. Given that events A and B are independent with P(A)=0.3 P(A)=0.3 and P(BA)=0.89 P(B \mid A)=0.89 determine the value of P(B) P(B) , rounding to the nearest thousandth, if necessary.\newlineAnswer:
  1. Define Independent Events: Since events AA and BB are independent, the probability of BB occurring is not affected by the occurrence of AA. Therefore, P(BA)P(B|A) is the same as P(B)P(B). We can use the definition of independent events to find P(B)P(B).
  2. Calculate Probability of Both Events: For independent events AA and BB, the probability of both AA and BB occurring is the product of their individual probabilities: P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B).
  3. Given Probabilities: We are given P(A)=0.3P(A) = 0.3 and P(BA)=0.89P(B|A) = 0.89. Since AA and BB are independent, P(BA)=P(B)P(B|A) = P(B). Therefore, we can equate P(B)P(B) to 0.890.89.
  4. Final Probability Calculation: We have determined that P(B)=0.89P(B) = 0.89. This is the probability of event BB occurring, rounded to the nearest thousandth as required.

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