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Given 
sin(xy^(3))=y^(3), find 
(dy)/(dx) in terms of 
x and 
y
Answer Attempt 1 out of 2

Given sin(xy3)=y3 \sin \left(x y^{3}\right)=y^{3} , find dydx \frac{d y}{d x} in terms of x x and y y \newlineAnswer Attempt 11 out of 22

Full solution

Q. Given sin(xy3)=y3 \sin \left(x y^{3}\right)=y^{3} , find dydx \frac{d y}{d x} in terms of x x and y y \newlineAnswer Attempt 11 out of 22
  1. Differentiate with respect to x: Differentiate both sides of the equation with respect to xx.\newlineddx[sin(xy3)]=ddx[y3] \frac{d}{dx}[\sin(xy^3)] = \frac{d}{dx}[y^3] \newlineUsing the chain rule on the left side and the power rule on the right side,\newlinecos(xy3)ddx[xy3]=3y2dydx \cos(xy^3) \cdot \frac{d}{dx}[xy^3] = 3y^2 \cdot \frac{dy}{dx}
  2. Apply chain and power rule: Differentiate xy3xy^3 with respect to xx.\newlineddx[xy3]=y3+3xy2dydx \frac{d}{dx}[xy^3] = y^3 + 3xy^2 \cdot \frac{dy}{dx} \newlineHere, we used the product rule.

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