Q. Given sin(xy3)=y3, find dxdy in terms of x and yAnswer Attempt 1 out of 2
Differentiate with respect to x: Differentiate both sides of the equation with respect to x.dxd[sin(xy3)]=dxd[y3]Using the chain rule on the left side and the power rule on the right side,cos(xy3)⋅dxd[xy3]=3y2⋅dxdy
Apply chain and power rule: Differentiate xy3 with respect to x.dxd[xy3]=y3+3xy2⋅dxdyHere, we used the product rule.
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