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Given 
f(x)=2x^(2)+7x+1, find 
f(-5)
Answer:

Given f(x)=2x2+7x+1 f(x)=2 x^{2}+7 x+1 , find f(5) f(-5) \newlineAnswer:

Full solution

Q. Given f(x)=2x2+7x+1 f(x)=2 x^{2}+7 x+1 , find f(5) f(-5) \newlineAnswer:
  1. Substitute xx with 5-5: Given the function f(x)=2x2+7x+1f(x) = 2x^2 + 7x + 1, we need to find the value of f(5)f(-5). This means we will substitute xx with 5-5 in the function and simplify.\newlineCalculation: f(5)=2(5)2+7(5)+1f(-5) = 2(-5)^2 + 7(-5) + 1
  2. Calculate square of 5-5: First, calculate the square of 5-5.\newlineCalculation: (5)2=25(-5)^2 = 25
  3. Multiply 22 by square: Next, multiply 22 by the result of (5)2(-5)^2.\newlineCalculation: 2×25=502 \times 25 = 50
  4. Multiply 77 by 5-5: Now, multiply 77 by 5-5.\newlineCalculation: 7×(5)=357 \times (-5) = -35
  5. Add all terms together: Finally, add all the terms together: 5050 (from step 33), 35-35 (from step 44), and the constant term 11.\newlineCalculation: 5035+1=1650 - 35 + 1 = 16

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