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Let’s check out your problem:
Fully simplify.
\newline
(
−
4
x
2
y
5
)
3
\left(-4 x^{2} y^{5}\right)^{3}
(
−
4
x
2
y
5
)
3
\newline
Answer:
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Home
Math Problems
Algebra 2
Evaluate rational exponents
Full solution
Q.
Fully simplify.
\newline
(
−
4
x
2
y
5
)
3
\left(-4 x^{2} y^{5}\right)^{3}
(
−
4
x
2
y
5
)
3
\newline
Answer:
Identify base and exponent:
Identify the base and the exponent in
(
−
4
x
2
y
5
)
3
(-4x^{2}y^{5})^{3}
(
−
4
x
2
y
5
)
3
.
\newline
In
(
−
4
x
2
y
5
)
3
(-4x^{2}y^{5})^{3}
(
−
4
x
2
y
5
)
3
, the base is
−
4
x
2
y
5
-4x^{2}y^{5}
−
4
x
2
y
5
and the exponent is
3
3
3
.
Apply power of product rule:
Apply the power of a product rule, which states that
(
a
b
)
n
=
a
n
∗
b
n
(ab)^n = a^n * b^n
(
ab
)
n
=
a
n
∗
b
n
, to the base.
(
−
4
x
2
y
5
)
3
=
(
−
4
)
3
∗
(
x
2
)
3
∗
(
y
5
)
3
(-4x^{2}y^{5})^{3} = (-4)^3 * (x^{2})^3 * (y^{5})^3
(
−
4
x
2
y
5
)
3
=
(
−
4
)
3
∗
(
x
2
)
3
∗
(
y
5
)
3
Calculate each part:
Calculate each part separately.
\newline
(
−
4
)
3
=
−
4
×
−
4
×
−
4
=
−
64
(-4)^3 = -4 \times -4 \times -4 = -64
(
−
4
)
3
=
−
4
×
−
4
×
−
4
=
−
64
\newline
(
x
2
)
3
=
x
(
2
×
3
)
=
x
6
(x^{2})^3 = x^{(2\times3)} = x^{6}
(
x
2
)
3
=
x
(
2
×
3
)
=
x
6
\newline
(
y
5
)
3
=
y
(
5
×
3
)
=
y
15
(y^{5})^3 = y^{(5\times3)} = y^{15}
(
y
5
)
3
=
y
(
5
×
3
)
=
y
15
Combine results:
Combine the results from Step
3
3
3
.
\newline
(
−
4
x
2
y
5
)
3
=
−
64
×
x
6
×
y
15
(-4x^{2}y^{5})^{3} = -64 \times x^{6} \times y^{15}
(
−
4
x
2
y
5
)
3
=
−
64
×
x
6
×
y
15
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