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Frank and his brother are at a store shopping for a beanbag chair for their school's library. The store sells beanbag chairs with different fabrics and types of filling.\newlineThe probability that a beanbag chair is made from suede is 0.60.6, the probability that it is filled with beads is 0.20.2, and the probability that it is made from suede and is filled with beads is 0.10.1.\newlineWhat is the probability that a randomly chosen beanbag chair is made from suede or is filled with beads?\newlineWrite your answer as a whole number, decimal, or simplified fraction.

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Q. Frank and his brother are at a store shopping for a beanbag chair for their school's library. The store sells beanbag chairs with different fabrics and types of filling.\newlineThe probability that a beanbag chair is made from suede is 0.60.6, the probability that it is filled with beads is 0.20.2, and the probability that it is made from suede and is filled with beads is 0.10.1.\newlineWhat is the probability that a randomly chosen beanbag chair is made from suede or is filled with beads?\newlineWrite your answer as a whole number, decimal, or simplified fraction.
  1. Denote Events: Let's denote the events as follows:\newlineA: The beanbag chair is made from suede.\newlineB: The beanbag chair is filled with beads.\newlineWe are given the following probabilities:\newlineP(A)=0.6P(A) = 0.6\newlineP(B)=0.2P(B) = 0.2\newlineP(A and B)=0.1P(A \text{ and } B) = 0.1
  2. Use Addition Rule: We need to find the probability that a randomly chosen beanbag chair is made from suede or is filled with beads. We can use the Addition Rule of Probability:\newlineP(A or B)=P(A)+P(B)P(A and B)P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)
  3. Substitute Given Values: Substituting the given values, we get: P(A or B)=0.6+0.20.1P(A \text{ or } B) = 0.6 + 0.2 - 0.1
  4. Correct Calculation: Solving this, we get:\newlineP(A or B)=0.7P(A \text{ or } B) = 0.7\newlineBut wait, I made a mistake in the calculation. It should be:\newlineP(A or B)=0.6+0.20.1=0.7P(A \text{ or } B) = 0.6 + 0.2 - 0.1 = 0.7

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