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Franco has 8080 $\$ in an account. The interest rate is 5%5\% compounded annually. To the nearest cent, how much will he have in 33 years? Use the formula B=p(1+r)tB = p(1 + r)^t, where BB is the balance (final amount), pp is the principal (starting amount), rr is the interest rate expressed as a decimal, and tt is the time in years. $\$____

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Q. Franco has 8080 $\$ in an account. The interest rate is 5%5\% compounded annually. To the nearest cent, how much will he have in 33 years? Use the formula B=p(1+r)tB = p(1 + r)^t, where BB is the balance (final amount), pp is the principal (starting amount), rr is the interest rate expressed as a decimal, and tt is the time in years. $\$____
  1. Identify values: Identify the principal amount pp, interest rate rr, and time tt.\newlinePrincipal pp = $80\$80\newlineInterest rate rr = %5 or $0.05\$0.05 as a decimal\newlineTime tt = 33\) years
  2. Plug into formula: Plug the values into the compound interest formula B=p(1+r)tB = p(1 + r)^t.\newlineB=80(1+0.05)3B = 80(1 + 0.05)^3
  3. Calculate inside parentheses: Calculate the value inside the parentheses first. 1+0.05=1.051 + 0.05 = 1.05
  4. Raise to power: Raise 1.051.05 to the power of 33. \newline(1.05)3=1.157625(1.05)^3 = 1.157625
  5. Multiply principal amount: Multiply the principal amount by the result from step 44.\newlineB=80×1.157625B = 80 \times 1.157625\newlineB=92.61B = 92.61

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