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For the function 
f(x) given below, evaluate

{:[lim_(x rarr oo)f(x)" and "lim_(x rarr-oo)f(x).],[quad f(x)=5sin(4x^(3))]:}

For the function f(x) f(x) given below, evaluate\newlinelimxf(x) and limxf(x).f(x)=5sin(4x3) \begin{array}{l} \lim _{x \rightarrow \infty} f(x) \text { and } \lim _{x \rightarrow-\infty} f(x) . \\ \quad f(x)=5 \sin \left(4 x^{3}\right) \end{array}

Full solution

Q. For the function f(x) f(x) given below, evaluate\newlinelimxf(x) and limxf(x).f(x)=5sin(4x3) \begin{array}{l} \lim _{x \rightarrow \infty} f(x) \text { and } \lim _{x \rightarrow-\infty} f(x) . \\ \quad f(x)=5 \sin \left(4 x^{3}\right) \end{array}
  1. Consider sine function behavior: To find the limit as xx approaches infinity, we need to consider the behavior of the sine function. The sine function oscillates between 1-1 and 11, no matter how large xx gets.
  2. Behavior of 4x34x^3: Since 4x34x^3 will become very large as xx approaches infinity, the argument of the sine function will also become very large. This means the sine function will keep oscillating.
  3. Limit as xx approaches infinity: Because the sine function oscillates and doesn't approach a single value, the limit of 5sin(4x3)5\sin(4x^3) as xx approaches infinity does not exist.
  4. Behavior as xx approaches negative infinity: Similarly, as xx approaches negative infinity, 4x34x^3 will become very large in the negative direction, and the sine function will continue to oscillate between 1-1 and 11.
  5. Conclusion: Therefore, the limit of 5sin(4x3)5\sin(4x^3) as xx approaches negative infinity also does not exist.

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